Digital Comminication
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Get it written →EE352- Digital Communication Exercise [Chapter (9)] Name: ID: Date: 1- Consider 16 possible message signals transmitted using PAM. The signal interval is 0.1 msec. Find: a. Symbol rate (baud rate) b. Bit rate 2- Consider 4 message signals as shown below: a. Find energy of each signal. b. If the probability of messages š 1 (š”), š 1 (š”), š 1 (š”) and š 1 (š”) are š = [0.1 0.3 0.5 0.1]. Find the average signal energy per symbol. c. Find average energy per bit. d. If equiprobable signals. Find the average signal energy per symbol. 3- For M message signals we use PAM modulator š š (š”) = š“š š(š”), For each case find average signal energy (assume equiprobable signals). š(š”) a. š = 2 , š“ = {±1} š(š”) b. š = 2 , š“ = {±1} c. š = 4 , š“ = {±1, ±3} d. š = 4 , š“ = {±1, ±3} š š 4- Suppose šÆā = ( š ) and š® ā =( š ) −š −š a. Find 〈v ā ,u ā〉 b. Find 〈u ā ,u ā〉 c. Find 〈v ā ,v ā〉 d. Find ||v ā || e. Find ||u ā || š(š”) š(š”) 5- Consider the four vectors below: −š −š š š šÆā (š) = (−š) , šÆā (š) = (−š) , šÆā (š) = ( š ) , šÆā (š) = ( š ) š š −š −š Represent these vectors in one-dimensional representation. −1 2 5 5 0 −1 6- Consider three vectors: v ā (1) = ( ) , āv (2) = ( ) , āv (3) = ( ). Let : −5 0 1 1 −2 −5 1 −1 1 1 1 1 eā(1) = 2 ( ) , eā(2) = 2 ( ) −1 −1 −1 1 a. Show that eā(1) and eā(2) are orthonormal. b. Calculate the following inner products: 〈v ā (1) , eā(1) 〉 = 〈v ā (1) , eā(2) 〉 = 〈v ā (2) , eā(1) 〉 = 〈v ā (2) , eā(2) 〉 = 〈v ā (3) , eā(1) 〉 = 〈v ā (3) , eā(2) 〉 = c. Suppose we use eā(1) and eā(2) as the new axes. Find the corresponding vectors c (1) , c (2) and c (3) that represent v ā (1) , v ā (2) and v ā (3) in the new coordinate system defined by eā(1) and eā(2) . 7- Consider the two signals š 1 (š”) and š 2 (š”) shown below. a. Find the energy of each signal. b. Find their inner product 〈š 1 (š”), š 2 (š”)〉. 8- Consider the four waveforms as shown below: Consider the following orthonormal functions: a) ∅1 (š”) = b) ∅2 (š”) = š 1 (š”) √šøš 1 š 2 (š”) √šøš 2 = = c) ∅3 (š”) = š 3 (š”) − š 1 (š”) = Write the four previous signals waveforms in vector form. EE352- Digital Communication Exercise [Chapter (9) – Part B] Name: ID: Date: Notes: M-PAM M-PSK šš (š”) = š“š š(š”) š“š = 2š − 1 − š Basis: ∅(š”) = š(š”) √šøš , šš (š”) = š(š”) cos(2ššš š” + šš ) ļ šš (š”) = š“š √šøš ∅(š”) M-QAM šš (š”) = š“š (š¼) Basis: ∅1 (š”) = √ šøš š(š”) cos(2ššš š”) − š“š š(š”) cos(2ššš š”) šø šš (š”) = √ š š“š 2 (š¼) 2 Basis: ∅1 (š”) = √ šøš š(š”) cos(2ššš š”) ∅2 (š”) = −√ 2 šøš šø šø 2 2 š(š”) sin(2ššš š”) šš (š”) = √ š cos(šš ) ∅1 (š”) + √ š sin(šš ) ∅2 (š”) (š) š(š”) sin(2ššš š”) š“š (š¼) = š“š (š) = 2š − 1 − √š , š = 1,2, . . , √š 2 2š šš = š (š − 1) , š = 1,2, . . , š š = 1,2, . . , š ∅2 (š”) = −√ 2 šøš šø ∅1 (š”) + √ š 2 š(š”) sin(2ššš š”) š“š (š) ∅2 (š”) M-FSK šš (š”) = š“ cos(2ššš š”) šš = šāš , š = 1,2, . . , š M-ASK šš (š”) = š“š š(š”)cos(2ššš š”) š“š = 2š − 1 − š , š = 1,2, . . , š 1- Find the Gray code for the following binary block length (b): a. š = 1 b. š = 2 c. š = 3 1|Page 2- Draw the constellation diagrams for: 2-PAM 4-PAM ∅2 (š”) ∅(š”) Index (m) Binary Block (b) Amplitude (š“š ) ∅1 (š”) Vector š (š) Index (m) Binary Block (b) Amplitude (š“š ) BPSK QPSK ∅2 (š”) ∅2 (š”) Vector š (š) ∅1 (š”) Index (m) Binary Block (b) Phase (šš ) ∅1 (š”) Vector š (š) Index (m) Binary Block (b) Phase (šš ) Vector š (š) 8-PSK ∅2 (š”) ∅1 (š”) Index (m) Binary Block (b) Phase (šš ) Vector š (š) Index (m) Binary Block (b) Phase (šš ) Vector š (š) 2|Page 4-QAM ∅2 (š”) Index (m) Binary Block (b) Amplitude (š“š (š¼) ) (š“š (š) ) ∅1 (š”) Index (m) Binary Block (b) Amplitude (š¼) (š“ š ) (š“ š (š) Vector š (š) ) 16-QAM ∅2 (š”) Index (m) Binary Block (b) Amplitude (š“š (š¼) ) (š“š (š) ) ∅1 (š”) Index (m) Binary Block (b) Amplitude (š¼) (š“ š ) (š“ š (š) ) Vector š (š) Index (m) Binary Block (b) Amplitude (š¼) (š“ š ) (š“ š (š) ) Vector š (š) 3|Page 3- Draw the transmitted signal for an input binary sequence (10001001) assuming: a. Amplitude Shift Keying (ASK) b. Frequency Shift Keying (FSK) c. Binary Phase Shift Keying (BPSK) a. ASK b. FSK c. BPSK 4|Page 4- You want to transmit the binary sequence (10010011) using a rectangular pulse š(š) with amplitude šØ and duration š». a. Draw the transmitted signal š(š), assume PAM (M=2) with š»š = š». š» b. Draw the transmitted signal š(š), assume PAM (M=2) with šš = š». c. Draw the transmitted signal š(š), assume 4-PAM (M=4) with š»š = š». +3 +1 -1 -3 5- You want to transmit the binary sequence (10010011) using ASK signaling with: a. M=2, Carrier frequency šš = š⁄š» . š 5|Page b. M=4, Carrier frequency šš = š⁄š» . š +3 +1 -1 -3 6- You want to transmit the binary sequence (10010011) using M-PSK signaling with: a. š“ = š , Carrier frequency šš = š⁄š» . š b. š“ = š , Carrier frequency šš = š⁄š» . š 6|Page c. š“ = š , Carrier frequency šš = š⁄š» . š 7- You want to transmit the binary sequence (10010011) using M-FSK signaling with: a. š“ = š , āš = š⁄š» . š b. š“ = š , āš = š⁄š» . š 7|Page EE352- Digital Communication Exercise [Chapter (10)] Name: ID: Date: Problem 1. Determine the autocorrelation function š š„ (š) and the power šš„ of a low-pass random process with a white noise PSD šš„ (š) = š⁄2 as shown in figure below. šš„ (š) š⁄ 2 š −šµ Page 1 of 4 šµ Problem 2. Consider a random process š„ (š”) = š“ cos(2ššš š” + š) Where š“ and šš are constants and š is an RV uniformly distributed over (0 , 2š). Determine: a) b) c) d) e) f) Page 2 of 4 Sketch the ensemble of this random process. The mean value. The autocorrelation function. The mean square value. The power spectral density. Is the process wide sense stationary? Problem 3. Consider a linear-time invariant (LTI) system shown below. If the PSD of the input signal given by šš„ (š) = 4 šæ(š − 10) and the transfer function of the system is š»(š) = the output signal šš¦ (š). š„(š”) š¦(š”) š»(š) Page 3 of 4 1 1+š 3š . Find the PSD of Problem 4. FIND THE 90% BANDWIDTH for the signal whose power spectral density is as given below: šš„ (š) 2 −20 Page 4 of 4 20 š Name_____________________ ID __________ EE 352: Digital Communications Exercise [Chapter 11] Problem 1. Assume M=4. Draw a block-diagram of a maximum-a-posteriori probability (MAP) receiver that uses the following decision rule. š Ģ (š(š”)) = šā ā¶ ā = argmax Pr{š = šš |š(š”)} š Problem 2. Assume M=4. Draw a block-diagram of a maximum likelihood (ML) receiver that uses the following decision rule. š Ģ (š(š”)) = šā ā¶ Page 1 of 5 ā = argmax Pr{š (š”) | šš šš š ššš”} š Problem 3. Assume M=4. Draw a block-diagram of a minimum Euclidean distance (MED) receiver that uses the following decision rule. šš š Ģ (š(š”)) = šā ā¶ ā = argmax ∫ š(š”) š§š (š”)šš” − š šøš⁄ 2 0 Problem 4. Assume M=4. Draw a block-diagram of a matched filter (MF) receiver and correlator receiver that use the following decision rule. š Ģ (š(š”)) = šā ā¶ ā = argmax š(š”) ∗ š§š (šš − š”)|š”=(š+1)š − šøš⁄ š š 2 š(š”) š§š (š” − ššš )šš” − šøš⁄ 2 (š+1)šš š Ģ (š(š”)) = šā ā¶ Page 2 of 5 ā = argmax ∫ š ššš Problem 5. Assume a Minimum Euclidean Distance reciver using correlator as shown below, For š = 2. The received signal alternatives are such that š§0 (š”) = − š§1 (š”) and, š§1 (š”) šµ šš 2 šš š” Furthermore, assume a noisefree situation and that š(š”) = š§1 (š”). Calculate the two decision variables š0 , š1 , and also the decision š Ģ . Is the decision correct? Page 3 of 5 Problem 6. Assume a Minimum Euclidean Distance reciver using correlator as shown below, For š = 2. The received signal alternatives are such that š§0 (š”) = − š§1 (š”) and, š§1 (š”) šµ šš 2 šš š” Furthermore, assume š(š”) = š§1 (š”) + š(š”), where š(š”) is AWGN eith power spectral density š0⁄ V 2⁄ 2 [ Hz]. Due to the noise š(š”), the decision variables š0 , š1 also contain a noise component š (š¤ and −š¤ respectively). The noise š¤ has zero mean and variance šš¤2 = 20 šø0 (where šø0 is the energy of signal š§0 (š”)). Determine the probability of a “miss” in terms of the š()-function. šø Calculate šš , if 0⁄š is 12.55 [dB]. 0 Page 4 of 5 Problem 7. a) Assume š0 = š1 and a Minimum Euclidean Distance reciver using correlator. How large šøš ⁄š in dB, is needed to obtain šš = 10−5 if the received signal alternatives š§0 (š”) ššš š§1 (š”) 0 are antipodal signals. b) Repeat the calculation in (a) but assume orthogonal signals. Page 5 of 5
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