Java Question
THIS IS THE ANSWER: Here’s a Java code snippet that uses the Sieve of Eratosthenes algorithm to find prime numbers between 2 and 999 and write them to a text file named “primes.txt”: “`java import java.io.FileWriter; import java.io.IOException; import java.io.PrintWriter; public class PrimeNumberFinder { public static void main(String[] args) { int n = 1000; boolean[] primes = new boolean[n]; for (int i = 2; i < n; i++) { primes[i] = true; } for (int p = 2; p * p < n; p++) { if (primes[p]) { for (int i = p * p; i < n; i += p) { primes[i] = false; } } } try { PrintWriter outputFile = new PrintWriter(new FileWriter(“primes.txt”)); int count = 0; for (int i = 2; i < n; i++) { if (primes[i]) { outputFile.println(i); count++; } } outputFile.println(); outputFile.println(“Total number of prime numbers: ” + count); outputFile.close(); System.out.println(“Prime numbers have been written to primes.txt”); } catch (IOException e) { System.out.println(“File Not Found”); } } } “` This code initializes an array of boolean values to track prime numbers using the Sieve of Eratosthenes algorithm. It then loops through the array to find prime numbers and writes them to the “primes.txt” file. Finally, it prints the total number of prime numbers found. Please note that you need to handle the `IOException` by catching it and displaying the “File Not Found” message to the console, as specified in the requirements
HERE’S THE QUESTION:
.A prime number is any integer greater than 1 that’s evenly divisible only by itself and 1. The Sieve of Eratosthenes is a method of finding prime numbers. It operates as follows:
a) Create a Boolean array with all elements initialized to true. Array elements with prime indices will remain true. All other array elements will eventually be set to false.
b) Starting with array index 2, determine whether a given element is true. If so, loop through the remainder of the array and set to false every element whose index is a multiple of the index for the element with value true. Then continue the process with the next element with value true. For array index 2, all elements beyond element 2 in the array that have indices which are multiples of 2 (indices 4, 6, 8, 10, etc.) will be set to false; for array index 3, all elements beyond element 3 in the array that have indices which are multiples of 3 (indices 6, 9, 12, 15, etc.) will be set to false; and so on.
When this process is completed, the array elements that are still true indicate that the index is a prime number. These indices can be displayed. Write an application that uses an array of 1,000 elements to determine and writes the prime numbers between 2 and 999 and the number of these prime numbers to a text file named “primes.txt”. Ignore array elements 0 and 1. Include code to handle the FileNotFound exception and display “File Not Found” message to the console should the exception occur.
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