Given the network plan that follows, compute the early, late, and slack times. Using any approach you wish (e.g., trial and error), develop a loading chart for resource, electrical eng

Use the attached spreadsheet template to complete the assignment.  Click on each of the tabs in the template to view each of the exercises.  

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Ch 8 Ex 4

PMT472 3.2 ASSIGNMENT: WEEK 3 EXERCISES
CH. 8 EXERCISE 4
Given the network plan that follows, compute the early, late, and slack times. Using any approach you wish (e.g., trial and error), develop a loading chart for resource, electrical engineers (EE), and resource, mechanical engineers (ME).
Start 0 1 4 5 End Legend
EE EE ME ES ID EF
2 1 6 SL Resource SL
LS DUR LF
0 2 6
EE ME
4 2
0 3 7
ME EE
3 4
Loading Schedule
EE
ME
0 1 2 3 4 5 6 7 8 9 10 11 12
What is the project duration?
(Enter response)
Assume only one of each resource exists. Given your adjusted loading schedule, compute the early, late, and slack times for your project in the resource activity schedule.
Loading Schedule (adjusted for resource constraint)
EE
ME
0 1 2 3 4 5 6 7 8 9 10 11 12
Resource Activity Schedule (with resource constraint)
ID/RES ES LS EF LF SL
1-EE
2-EE
3-ME
4-EE
5-ME
6-ME
7-EE
Which activities are now critical?
(Enter response)
What is the project duration now?
(Enter response)
Could something like this happen in real projects?
(Enter response)

Ch 9 Ex 1

PMT472 3.2 ASSIGNMENT: WEEK 3 EXERCISES
CH. 9 EXERCISE 1
Use the following information to compress one time unit per move using the least-cost method. Reduce the schedule until you reach the crash point of the network. For each move identify what activity or activities were crashed and the adjusted total direct cost. Note: The correct normal project duration, critical path, and total direct cost are provided. The crash cost is how much extra it will cost to crash the activity per time unit reduced. The maximum crash time is how many time units the activity can be reduced by. E.g. Activity D can be reduced by 2 time units down to 1 time unit for a total additional cost of $120.
Activity Crash Cost (slope) Maximum Crash Time Normal Time Normal Cost
A $50 1 3 $150
B $100 1 3 $100
C $60 2 4 $200
D $60 2 3 $200
E $70 1 4 $200
F $0 0 1 $150
Crash Round 1 B D What was crashed: Activity A was reduced by 1 day (or time unit) from 3 days to 2 days.
3 3 Adjusted total direct cost: $1,050
A F The cheapest activity to reduce is A so we reduce it by its maximum reduction of one time unit to two time units. The A-C-E-F path remains critical at 11 time units and direct costs go up to $1,050 since it cost $50 to crash A.
2 1
C E
4 4
Crash Round 2 B D What was crashed: (Enter response)
Adjusted total direct cost: (Enter response)
A F
C E
Crash Round 3 B D What was crashed: (Enter response)
Adjusted total direct cost: (Enter response)
A F
C E
Crash Round 4 B D What was crashed: (Enter response)
Adjusted total direct cost: (Enter response)
A F
C E

Ch 9 Ex 2

PMT472 3.2 ASSIGNMENT: WEEK 3 EXERCISES
CH. 9 EXERCISE 2
Use the following information contained below to compress one time unit per move using the least-cost method.* Reduce the schedule until you reach the crash point of the network. For each move identify what activity or activities were crashed and the adjusted total direct cost. Note: Choose B instead of C and E (equal costs) because it is usually smarter to crash early rather than late AND one activity instead of two activities.
Activity Crash Cost (slope) Maximum Crash Time Normal Time Normal Cost
A $0 2 $150
B $100 1 3 $100
C $50 2 6 $200
D $40 1 4 $200
E $50 1 3 $200
F $0 0 1 $150
Crash Round 1 C What was crashed: (Enter response)
Adjusted total direct cost: (Enter response)
A B F
D E
Crash Round 2 C What was crashed: (Enter response)
Adjusted total direct cost: (Enter response)
A B F
D E
Crash Round 3 C What was crashed: (Enter response)

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